Question

If $a^m\cdot a^n=a^{mn}$, then $m(n-2)+n(m-2)$ is

• A. $1$
• B. $-1$
• C. $0$
• D. $\frac{1}{2}$

Answer 1

The correct option is C $0$

$a^m\cdot a^n=a^{mn}⟹m+n=mn$
$⟹m(n-2)+n(m-2)=2mn-2(m+n)=2mn-2mn=0$