If $a^{n + 2}$ = $a^{2 n - 1},$ then the value of $n$ is __.

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Solution

The correct option is A
3

Consider the equation $a^{n + 2}$ = $a^{2 n - 1} .$

Since the bases of the powers are equal, so should the exponents be.
$⟹ n + 2 = 2 n - 1$
$⟹ 2 + 1 = 2 n - n$
$⟹ n = 3$

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