If a normal cab fare is ₹293.50, then 2.5 times the fare will be ____________.

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Solution

The normal cab fare = ₹293.50
Hence 2.5 times the fare = ₹293.50 $\times$ 2.5
= $\frac{29350 \times 25}{100 \times 10} = \frac{733750}{1000}$
= ₹733.75

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If a normal cab fare is ₹293.50, then 2.5 times the fare will be ____________.

The normal cab fare = ₹293.50 Hence 2.5 times the fare = ₹293.50 × 2.5 = 29350×25100×10=7337501000 = ₹733.75

The normal cab fare = ₹293.50
Hence 2.5 times the fare = ₹293.50 $\times$ 2.5
= $\frac{29350 \times 25}{100 \times 10} = \frac{733750}{1000}$
= ₹733.75