Question

If a number is 20% more than the other, how much percent is the second number less than the first?

• A. $12\frac{1}{3}\%$
• B. $16\frac{2}{3}\%$
• C. $16\frac{1}{3}\%$
• D. None of these

Answer 1

The correct option is B $16\frac{2}{3}\%$

Here, x = 20
$\therefore Requiredanswer=(\frac{x}{100+x}\times 100)\%$

$=(\frac{20}{100+20}\times 100)\%$
$=16\frac{2}{3}\%$