Question

If a particle is thrown vertically upward, then its maximum height so that it covers same distances during 5th and 6th second would be

• A. 125 m
• B. 250 m
• C. 500 m
• D. 75 m

Answer 1

The correct option is A 125 m

Since, the particle travels equal distance in $5th$ and $6th$ second therefore, it reaches the maximum height in $5s$.

The initial velocity of the particle is,

$v=u+gt$

$0=u+\left(-9.8\right)\times 5$

$u=49m/s$

The maximum height it reached is,

$h=ut+\frac{1}{2}g{t}^2$

$=49\times 5+\frac{1}{2}\left(-9.8\right)\times 5^2$

$=122.5m$