Question

If a particle moves towards east with a velocity Q $5m{s}^{-1}.$ In 10 seconds. The velocity changes to $5ms-1$ north. Find avg. acceleration Q particle.

Answer 1

$u=5i$ and $v=5j$

$a=\frac{v-u}{t}=\frac{5j-5i}{10}$

$⟹a=\frac{1}{2}(j-i)$

Magnitude of acceleration is $a=\frac{\sqrt{2}}{2}=\frac{1}{\sqrt{2}}$

Hence, acceleration is $\frac{1}{\sqrt{2}}m/s^2$ and direction is north-west.