If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force (−kr2), the total energy is
(−k2r)
(−kr)
(−2kr)
(−4kr)
mv2r=kr2⇒mv2=kr ∴ K.E.=12mv2=k2r P.E.=∫F dr=∫kr2dr=−kr ∴ Total energy=K.E.+P.E.=k2r−kr=−k2r
A particle of mass m is moving in a horizontal circle of radius r under a centripetal force equal to −Kr2 , where K is a constant. The total energy of the particle is