If a particle under S.H.M. has time period 0.1 sec and amplitude 2x $10^{- 3}$ m. It has maximum velocity

[RPET 2000]

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Solution

The correct option is A

$v_{m a x} = a ω = \frac{a \times 2 π}{T} = \frac{2 \times 10^{- 3} \times 2 π}{0.1} = \frac{π}{25}$ m/s

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If a particle under S.H.M. has time period 0.1 sec and amplitude 2x10−3 m. It has maximum velocity [RPET 2000]

The correct option is A vmax=aω=a×2πT=2×10−3×2π0.1=π25 m/s

If a particle under S.H.M. has time period 0.1 sec and amplitude 2x $10^{- 3}$ m. It has maximum velocity

[RPET 2000]

The correct option is A

$v_{m a x} = a ω = \frac{a \times 2 π}{T} = \frac{2 \times 10^{- 3} \times 2 π}{0.1} = \frac{π}{25}$ m/s