If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity is

[AIIMS 1998; MH CET 2000; DPMT 2000]

0.10 m / s

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0.15 m / s

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0.8 m / s

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0.26 m / s

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Solution

The correct option is B
0.15 m / s

$v_{m a x} = a ω = a \times \frac{2 π}{T} = (50 \times 10^{- 3}) \times \frac{2 π}{2} = 0.15 m / s$

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If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity is [AIIMS 1998; MH CET 2000; DPMT 2000]

The correct option is B 0.15 m / s vmax=aω=a×2πT=(50×10−3)×2π2=0.15m/s

If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity is

[AIIMS 1998; MH CET 2000; DPMT 2000]

The correct option is B
0.15 m / s

$v_{m a x} = a ω = a \times \frac{2 π}{T} = (50 \times 10^{- 3}) \times \frac{2 π}{2} = 0.15 m / s$