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Question

If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 seconds, then its maximum velocity is

A
0.8 m/s
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B
0.5 m/s
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C
2.1 m/s
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D
0.16 m/s
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Solution

The correct option is D 0.16 m/sGiven : Time period T=2 seconds; amplitude of pendulum A=50 mm=0.05 m We know that the velocity of a simple pendulum undergoing SHM is given by ∴vmax=2πTA ∴vmax=2π2×0.05=0.16 m/s Hence, the correct answer is option (d). Why this question? Note: In simple harmonic motion, maximum velocity occurs at mean position.

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