Question

If a person can jump 1 m at the surface of the earth, he will be able to jump 6 metres at the surface of the moon. Therefore, the ratio of moon's acceleration due to gravity to earth's acceleration due to gravity, taken at the surfaces, would be

• A. 6
• B. 1/6
• C. 0.6
• D. 0.06

Answer 1

The correct option is B 1/6

By using third equation of motion, we know that

$\Rightarrow h=\frac{u^2}{2g}$

$\Rightarrow h$ $\alpha$ $\frac{1}{g}$ [$\because u$ is constant]

$\Rightarrow \frac{h_e}{h_m}=\frac{g_m}{g_e}$

$\Rightarrow \frac{g_m}{g_e}=\frac{1}{6}$

Hence correct answer is option $B$