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Question

If a polynomial gives remainder 1 and 2 and same quotient on dividing by x−2 and x−1 respectively, then the remainder when that polynomial is divided by x2−3x+2, is

A
x3
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B
x+3
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C
x2
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D
x+2
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Solution

The correct option is B x+3
when p(x) is divided by x23x+2 then remainder should be of the form ax+b as degree of remainder should be less than the divisor
according to the given in the question, p(1)=2 and p(2)=1
p(x)=(x23x+2)h(x)+ax+b
p(1)=a+b=2 and p(2)=2a+b=1
using these two equations,a=1 & b=3
hence remainder=x+3

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