Question

If a resistance of 20 $\Omega$ is connected parallel to a galvanometer of internal resistance 100 ohm, the part of the current in the circuit passes through galvanometer is

• A. 1/6
• B. 1/4
• C. 1/5
• D. 1/8

Answer 1

The correct option is A 1/6

$Req=\frac{20\times 100}{20+100}=\frac{100}{6}$

let current passing through galvanometer be i

= $i\left(100\right)=i^1\left(\frac{100}{6}\right)$

$\therefore i=\frac{i^1}{6}$

$\therefore \frac{1^{th}}{6}$ of current passes through galvanometer