If a source emitting waves of frequency f moves towards an observer with a velocity v/3 and the observer moves away from the source with a velocity v/4, the apparent frequency as heard by the observer will be : (v = velocity of sound)

(9/8) f

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(8/9) f

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(3/4) f

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(4/3) f

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Solution

The correct option is C (9/8) f
Apparent frequency:
$f_{1} = (\frac{v - v_{o}}{v - v_{s}}) f$
$= ⎛ ⎜ ⎜ ⎝ \frac{v - \frac{v}{4}}{v - \frac{v}{3}} ⎞ ⎟ ⎟ ⎠ f$
$= ⎛ ⎜ ⎜ ⎜ ⎝ \frac{\frac{3 v}{4}}{\frac{2 v}{3}} ⎞ ⎟ ⎟ ⎟ ⎠ f$
$f_{1} = (\frac{9}{8}) f$

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If a source emitting waves of frequency f moves towards an observer with a velocity v/3 and the observer moves away from the source with a velocity v/4, the apparent frequency as heard by the observer will be : (v = velocity of sound)

The correct option is C (9/8) fApparent frequency: f1=(v−vov−vs)f =⎛⎜ ⎜⎝v−v4v−v3⎞⎟ ⎟⎠f =⎛⎜ ⎜ ⎜⎝3v42v3⎞⎟ ⎟ ⎟⎠ff1=(98)f

The correct option is C (9/8) f
Apparent frequency:
$f_{1} = (\frac{v - v_{o}}{v - v_{s}}) f$
$= ⎛ ⎜ ⎜ ⎝ \frac{v - \frac{v}{4}}{v - \frac{v}{3}} ⎞ ⎟ ⎟ ⎠ f$
$= ⎛ ⎜ ⎜ ⎜ ⎝ \frac{\frac{3 v}{4}}{\frac{2 v}{3}} ⎞ ⎟ ⎟ ⎟ ⎠ f$
$f_{1} = (\frac{9}{8}) f$