Question

If a spring extends by x on loading, then the energy stored by the spring is (if T is tension in the spring and k is spring constant)

• A. $\frac{T^2}{2x}$
• B. $\frac{T^2}{2K}$
• C. $\frac{2x}{T^2}$
• D. $\frac{2T^2}{k}$

Answer 1

The correct option is B $\frac{T^2}{2K}$

b) Potential energy stored in spring
kx = T
:$U=\frac{k{x}^2}{2}$
$U=\frac{F^2}{2K}=\frac{T^2}{2K}$