Question

The spring extends by x on loading, then energy stored by the spring is (if T is the tension in spring and k spring constant).

• A. $\frac{T^2}{2k}$
• B. $\frac{T^2}{2k^2}$
• C. $\frac{2k}{T^2}$
• D. $\frac{2T^2}{k}$

Answer 1

The correct option is A $\frac{T^2}{2k}$

$T=kx;x=\frac{T}{k}$
energy stored by the spring is$=\frac{1}{2}k{x}^2=\frac{1}{2}k(\frac{T}{k}{)}^2=\frac{T^2}{2k}$