If a square $A B C D$ is inscribed in a circle and $A B = 4 c m$ , the radius of the circle is:

2 c m

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2 \sqrt{2} c m

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1 c m

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\frac{1}{\sqrt{2}} c m

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Solution

The correct option is B $2 \sqrt{2} c m$
R.E.F image
AB = 4 cm (Given)
In $△ A O B$
using Pythagoras theorem
$A B^{2} = A D^{2} + B D^{2}$
$4^{2} = μ^{2} + μ^{2}$
$2 μ^{2} = 16$
$μ^{2} = 8$
$μ = 2 \sqrt{2}$
Hence,option B

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If a square ABCD is inscribed in a circle and AB=4cm, the radius of the circle is:

The correct option is B 2√2cmR.E.F imageAB = 4 cm (Given)In △AOBusing Pythagoras theoremAB2=AD2+BD242=μ2+μ22μ2=16μ2=8μ=2√2 Hence,option B

If a square $A B C D$ is inscribed in a circle and $A B = 4 c m$ , the radius of the circle is:

The correct option is B $2 \sqrt{2} c m$
R.E.F image
AB = 4 cm (Given)
In $△ A O B$
using Pythagoras theorem
$A B^{2} = A D^{2} + B D^{2}$
$4^{2} = μ^{2} + μ^{2}$
$2 μ^{2} = 16$
$μ^{2} = 8$
$μ = 2 \sqrt{2}$
Hence,option B