Question

If a tower 30 m high, casts a shadow $10\sqrt{3}$ m long on the ground, then what is the angle of elevation of the sun?

Answer 1

In $△$ ABC,
Let AB be the tower and BC be its shadow.

tan $\theta =\frac{AB}{BC}$



tan $\theta =\frac{30}{10\sqrt{3}}=\sqrt{3}$

tan $\theta =tan{60}^{\circ }\Rightarrow \theta ={60}^{\circ }$