If a triangle and a parallelogram are on the same base and between same parallels, then what is the ratio of the area of the triangle to the area of the parallelogram?

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Solution

R.E.F image
Area (ABD) $= \frac{1}{2} \times h \times b$ (approx.)
as the other half triangle is also
the half if parallelogram.
&
Area (ABCD) $= h \times b$ .
$∴$ ratio of $△$ to parallelogram
= $\frac{1}{2}$

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If a triangle and a parallelogram are on the same base and between same parallels, then what is the ratio of the area of the triangle to the area of the parallelogram?

R.E.F imageArea (ABD)=12×h×b (approx.)as the other half triangle is alsothe half if parallelogram.&Area (ABCD)=h×b.∴ ratio of △ to parallelogram= 12

R.E.F image
Area (ABD) $= \frac{1}{2} \times h \times b$ (approx.)
as the other half triangle is also
the half if parallelogram.
&
Area (ABCD) $= h \times b$ .
$∴$ ratio of $△$ to parallelogram
= $\frac{1}{2}$