Question

If a TV of rating 100W is operated for 6 hrs per day, What is the number of units consumed in any leap year ?

• A. 219.6 kWhr
• B. 218.6 kWhr
• C. 215.8 kWhr
• D. 315.2 kWhr

Answer 1

The correct option is A 219.6 kWhr

It is given that the total power of the TV is 100 W and it is operated 6 hr/day.
The total number of days in a leap year is 366 days. Hence, the total time taken in a leap year is given as $6hours\times 366days=2196hours$.
The electric power in watts associated with a complete electric circuit or a circuit component represents the rate at which energy is converted from the electrical energy of the moving charges to some other form, e.g., heat, mechanical energy, or energy stored in electric fields or magnetic fields. The power is given by the product of applied voltage and the electric current. That is, P=VI.
The heat produced or the energy dissipated by an appliance is given by the product of power and time taken in seconds. That is, Q=Pt.
So, $Q=P\times t=100W\times 2196hrs=219600Wh=219.6kWh.$
1 kWh = 1 unit.
Hence, the number of units consumed by the TV in any leap year is 219.6 units.