If A - x- -1 x 1- x - B - x- x -0 or x - 2- x - and A - B - - - C- then set C is

A∪ nbsp;B = (−1, 1) ∪ ( ∞, 0] ∪ [2, ∞) = ( ∞, 1) ∪ [2, ∞) = ℝ [1,2) ...

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Intervals as Subsets of Real Numbers

If A = x: −1 ...

Question

If $A = {x : - 1 < x < 1; x \in R}$ , $B = {x : x \leq 0 or x \geq 2; x \in R}$ and $A \cup B = R - C$ , then set $C$ is

{x : 1 < x < 2; x \in R}

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{x : 1 < x \leq 2; x \in R}

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{x : 1 \leq x < 2; x \in R}

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None of these

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Similar questions

(i) {x : x \in R, - 4 < x \leq 6}

(i i) {x : x \in R, - 12 < x < - 10}

(i i i) {x : x \in R, 0 \leq x < 7}

(i v) {x : x \in R, 3 \leq x \leq 4}

A = {(x, y) \in R \times R | 2 x^{2} + 2 y^{2} - 2 x - 2 y = 1},

B = {(x, y) \in R \times R | 4 x^{2} + 4 y^{2} - 16 y + 7 = 0}

C = {(x, y) \in R \times R | x^{2} + y^{2} - 4 x - 2 y + 5 \leq r^{2}}

| r |

A \cup B \subseteq C

A = {x \in R : | x | < 2}

B = {x \in R : | x - 2 | \geq 3},

If the sets $A$ and $B$ are defined as

$A = {(x, y) : y = \frac{1}{x}, x \in R - {0}}$

$B = {(x, y) : y = - x, x \in R}$ , then

A = {x : x \in R, 0 < x < 2}

B = {x : x \in R, 1 < x \leq 3}

A - B =

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