If A - x - x - R - 0- x -2- B - x - x - R - 1- x - 3- then A - B -A- 0-2B- 1-3- 0-1-D- 0-1

The correct option is C (0,1]A = {x: x ∈ℝ, 0 x 2}, B = {x: x ∈ℝ, 1 x ≤ 3} A ∩ B = {x: x ∈ℝ , 1 x 2} A − B = A − (A ∩ B) = {x: x ∈ℝ, 0 x ≤ 1} = (0, 1] ...

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Byju's Answer

Standard XII

Mathematics

Difference of Two Sets

If A = x : x ...

Question

If $A = {x : x \in R, 0 < x < 2}$ , $B = {x : x \in R, 1 < x \leq 3}$ , then $A - B =$

(0, 1)

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(0, 2)

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(1, 3]

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(0, 1]

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Solution

The correct option is D $(0, 1]$
$A = {x : x \in R, 0 < x < 2}$ ,
$B = {x : x \in R, 1 < x \leq 3}$
$A \cap B = {x : x \in R, 1 < x < 2}$
$A - B = A - (A \cap B) = {x : x \in R, 0 < x \leq 1} = (0, 1]$

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If A={x:x∈R,0<x<2}, B={x:x∈R,1<x≤3}, then A−B=

The correct option is D (0,1]A={x:x∈R,0<x<2}, B={x:x∈R,1<x≤3} A∩B={x:x∈R,1<x<2} A−B=A−(A∩B)={x:x∈R,0<x≤1}=(0,1]

If $A = {x : x \in R, 0 < x < 2}$ , $B = {x : x \in R, 1 < x \leq 3}$ , then $A - B =$

The correct option is D $(0, 1]$
$A = {x : x \in R, 0 < x < 2}$ ,
$B = {x : x \in R, 1 < x \leq 3}$
$A \cap B = {x : x \in R, 1 < x < 2}$
$A - B = A - (A \cap B) = {x : x \in R, 0 < x \leq 1} = (0, 1]$