If A=[x:xisamultipleof3]andB=[x:xisamultipleof5], then A–Bis
Finding the value of A–B:
Given A=[x:xisamultipleof3]andB=[x:xisamultipleof5],
A=[x:xisamultipleof3]A={3,6,9….}B=[x:xisamultipleof5]B={5,10,15….}A–(A∩B)=(A∩B[bar])A–B=[x:xisamultipleof3butnotamultipleof5]
Hence the value of A–Bis[x:xisamultipleof3butnotamultipleof5].
If A = {x : x is a multiple of 3} and , B = {x :x is a multiple of 5}, then A - B is
If A = {x: x is a multiple of 3} and B = {x: x is a multiple of 5}, then A - B is