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Question

If A=[x:xisamultipleof3]andB=[x:xisamultipleof5], then ABis


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Solution

Finding the value of AB:

Given A=[x:xisamultipleof3]andB=[x:xisamultipleof5],

A=[x:xisamultipleof3]A={3,6,9.}B=[x:xisamultipleof5]B={5,10,15.}A(AB)=(AB[bar])AB=[x:xisamultipleof3butnotamultipleof5]

Hence the value of ABis[x:xisamultipleof3butnotamultipleof5].


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