Question

If $A=\{x:xisamultipleof3\}andB=\{x:xisamultipleof5\}.$ Then, $A\cap B$ is given by

Answer 1

Finding the value of $A\cap B$:

Given $A=\{x:xisamultipleof3\}andB=\{x:xisamultipleof5\}.$

$$\begin{gathered} Multiplesof3=\{3,6,9,12,15,18,21,\dots .\} \\ A=\{3,6,9,12,15,18,21,\dots .\} \\ Multiplesof5=5,10,15,20,25,30\dots . \\ B=\{5,10,15,20,25,30\dots .\} \\ A\cap B=\{15,30\dots \dots .\} \end{gathered}$$

Hence the value of $\mathit{A}\mathbf{\cap }\mathit{B}\mathbf{}\mathit{i}\mathit{s}\mathbf{}\mathbf{\{}\mathbf{}\mathbf{15}\mathbf{,}\mathbf{30}\mathbf{\dots }\mathbf{\dots }\mathbf{.}\mathbf{\}}\mathbf{.}$