If AB CD and XY is transversal which meets AB at M and CD at N also - AM X -62- then - DNY - A- 62-B- 118-C- 122-

The correct option is A 62^∘ Given ∠ AMX=62^∘ Therefore ∠ BMY = 62^∘ (vertically opposite angles) ∠ BMY =∠ DNY (corresponding angles) So ∠ DNY = 62^∘ ...

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Byju's Answer

Standard VIII

Mathematics

Corresponding Angle Theorem and Its Converse

If AB CD and ...

Question

If AB || CD and XY is transversal which meets AB at M and CD at N also $∠ A M X = 62^{\circ}$ , then $∠ D N Y =$ .

62^{\circ}

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118

^{\circ}

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122

^{\circ}

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Solution

The correct option is A $62^{\circ}$

Given $∠ A M X = 62^{\circ}$
Therefore $∠ B M Y = 62^{\circ}$ (vertically opposite angles)
$∠ B M Y = ∠ D N Y$ (corresponding angles)
So $∠ D N Y = 62^{\circ}$

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If AB || CD and XY is transversal which meets AB at M and CD at N also ∠AMX=62∘, then ∠DNY=.

The correct option is A 62∘ Given ∠AMX=62∘ Therefore ∠BMY=62∘ (vertically opposite angles) ∠BMY=∠DNY (corresponding angles) So ∠DNY=62∘

If AB || CD and XY is transversal which meets AB at M and CD at N also $∠ A M X = 62^{\circ}$ , then $∠ D N Y =$ .

The correct option is A $62^{\circ}$

Given $∠ A M X = 62^{\circ}$
Therefore $∠ B M Y = 62^{\circ}$ (vertically opposite angles)
$∠ B M Y = ∠ D N Y$ (corresponding angles)
So $∠ D N Y = 62^{\circ}$