If AB is a chord of a circle with center O, and AC=BC, then x=90∘.
True
False
We know that the segment joining the centre of a circle and the midpoint of its chord is perpendicular to the chord. Hence, x=90∘.
If AB is a chord of a circle with center O, then x=90∘
Chords AB and CD of a circle with centre O, intersect at a point E. If OE bisects ∠AED, then chord AB = CD.
If each of two chords, AB and CD of a circle are at a distance of 4 cm from the center, then AB = CD.
In two concentric circles with centre O, if AD is the chord of the larger circle, then AB = CD.