If AB is a chord of a circle with center O, then x=90∘
90°
80°
The line bisecting a chord of a circle and passing through the center is perpendicular to the chord. Hence, x=90∘.
If AB is a chord of a circle with centre O. Then ∠x=90∘.
AB is a chord of a circle with centre O.
∠x=90∘
If AB is a chord of a circle with center O, and AC=BC, then x=90∘.
AB is a chord of a circle with centre O. AC = CB, ∠x=90∘