If AB is the object and CD is the image formed- If AP is the object distance and CP is the image distance from the mirror- Then choose the correct signconvention- begin array - hline5 - - AP - ve - 6 - - AP - velllhline7 - - PC - ve - 7 - - PC - velll hlinelend array A- concave mirror -1-3-5 - 7- plane mirror -1-3-5-7B- concave mirror -2-3-6 - 8- plane mirror -1-3-6-7C- concave mirror -2-3-6 - 8- plane mirror -1-3-6-8D- concave mirror -2-3-5-7- plane mirror -1-3-6

The correct option is B concave mirror – 2, 3, 6 amp; 8, plane mirror – 1, 3 , 6 , 7 ...

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Byju's Answer

Standard VII

Physics

Image Formed by Plane Mirror

If AB is the ...

Question

If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention?
$\begin{matrix} 1. height of image = + v e & 2. height of image = - v e 3. height of object = + v e & 4. height of object = - v e 5. A P = + v e & 6. A P = - v e 7. P C = + v e & 7. P C = + v e \end{matrix}$

concave mirror – 1, 3, 5 & 7, plane mirror – 1, 3, 5, 7

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concave mirror – 2, 3, 6 & 8, plane mirror – 1, 3 , 6 , 7

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concave mirror – 2, 3, 6 & 8, plane mirror – 1, 3, 6, 8

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concave mirror – 2, 3, 5, 7, plane mirror – 1, 3, 6,

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Solution

The correct option is B
concave mirror – 2, 3, 6 & 8, plane mirror – 1, 3 , 6 , 7

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Similar questions

If AB is an object, CD is an image formed. If AP is object distance CP is image distance from the mirror. Then choose the correct sign convention.

1. height of image = + ve 2. height of image = – ve

3. height of object = + ve 4. height of object = – ve

5. AP = + ve 6. AP = – ve

7. PC = + ve 8. PC = – ve.

AB refers to an object and CD is its image formed. If AP and CP are the object and image distances from the mirror, choose the correct sign convention:
$\begin{matrix} 1. height of image = + ve & 2. height of image = - ve 3. height of object = + ve & 4. height of object = - ve 5. AP = + ve & 6. AP = - ve 7. PC = + ve & 7. PC = + ve \end{matrix}$

Q. If AB is the object and CD is the image formed. If AP is the object distance and PC is the image distance from the mirror. Then choose the correct sign convention?
Assume that the object is beyond the focus in the case of concave mirror and new cartesian sign convention.

1. CD: Positive
2. CD: Negative
3. AB: Positive
4. AB: Negative
5. AP: Positive
6. AP: Negative
7. CP: Positive
8. CP: Negative

If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention?
$\begin{matrix} 1. h e i g h t o f i m a g e = + v e & 2. h e i g h t o f i m a g e = - v e 3. h e i g h t o f o b j e c t = + v e & 4. h e i g h t o f o b j e c t = - v e 5. A P = + v e & 6. A P = - v e 7. P C = + v e & 8. P C = - v e \end{matrix}$

Q. An object is placed at a distance of

2 f

from a concave mirror. Light reflected from the mirror falls on a plane mirror. The distance of the plane mirror from the concave mirror equals

f

. The distance of the final image from the concave mirror (due to reflection at both concave and plane mirror) is :

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If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention? 1.height of image=+ ve2. height of image=−ve3. height of object=+ve4. height of object=−ve5. AP=+ve6. AP=−ve7. PC=+ve7. PC=+ve

The correct option is B concave mirror – 2, 3, 6 & 8, plane mirror – 1, 3 , 6 , 7

The correct option is B
concave mirror – 2, 3, 6 & 8, plane mirror – 1, 3 , 6 , 7