If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention?
$\begin{matrix} 1. h e i g h t o f i m a g e = + v e & 2. h e i g h t o f i m a g e = - v e 3. h e i g h t o f o b j e c t = + v e & 4. h e i g h t o f o b j e c t = - v e 5. A P = + v e & 6. A P = - v e 7. P C = + v e & 8. P C = - v e \end{matrix}$

concave mirror - 1, 3, 5 & 7, plane mirror - 1, 3, 5, 7

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concave mirror - 2, 3, 6 & 8, plane mirror - 1, 3 , 6 , 7

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concave mirror - 2, 3, 6 & 8, plane mirror - 1, 3, 6, 8

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concave mirror - 2, 3, 5, 7, plane mirror - 1, 3, 6,

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Solution

The correct option is B
concave mirror - 2, 3, 6 & 8, plane mirror - 1, 3 , 6 , 7

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Similar questions

If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention?

1. height of image = + ve 2. height of image = – ve

3. height of object = + ve 4. height of object = – ve

5. AP = + ve 6. AP = – ve

7. PC = + ve 8. PC = – ve.

If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention?
$\begin{matrix} 1. & h e i g h t o f i m a g e = + v e & 2. & h e i g h t o f i m a g e = - v e 3. & h e i g h t o f o b j e c t = + v e & 4. & h e i g h t o f o b j e c t = - v e 5. & A P = + v e & 6. & A P = - v e 7. & P C = + v e & 8. & P C = - v e \end{matrix}$

Q. If AB is the object and CD is the image formed. If AP is the object distance and PC is the image distance from the mirror. Then choose the correct sign convention?
Assume that the object is beyond the focus in the case of concave mirror and new cartesian sign convention.

1. CD: Positive
2. CD: Negative
3. AB: Positive
4. AB: Negative
5. AP: Positive
6. AP: Negative
7. CP: Positive
8. CP: Negative

AB refers to an object and CD is its image formed. If AP and CP are the object and image distances from the mirror, choose the correct sign convention:
$\begin{matrix} 1. height of image = + ve & 2. height of image = - ve 3. height of object = + ve & 4. height of object = - ve 5. AP = + ve & 6. AP = - ve 7. PC = + ve & 7. PC = + ve \end{matrix}$

What sign (+ve or -ve) has been given to the following on the basis of Cartesian Sign Convention ? (a) Height of a real image. (b) Height of a virtual image.

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If AB is the object and CD is the image formed. If AP is the object distance and CP is the image distance from the mirror. Then choose the correct sign convention? 1. height of image=+ ve2. height of image=−ve3. height of object=+ve4. height of object=−ve5. AP=+ve6. AP=−ve7. PC=+ve8. PC=−ve

The correct option is B concave mirror - 2, 3, 6 & 8, plane mirror - 1, 3 , 6 , 7

The correct option is B
concave mirror - 2, 3, 6 & 8, plane mirror - 1, 3 , 6 , 7