If ABC is an isosceles triangle right angled at C, then which of the following is true?

A B^{2} = 2 A C^{2}

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2 A B^{2} = 5 A C^{2}

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A B^{2} = 3 A C^{2}

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3 A B^{2} = 5 A C^{2}

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Solution

The correct option is A $A B^{2} = 2 A C^{2}$

Given that $Δ A B C$ is an isosceles triangle right angled at C.
In $Δ A C B, ∠ C = 90^{\circ}$
AC = BC (Given)
$A B^{2} = A C^{2} + B C^{2}$ ([By using Pythagoras theorem]
$= A C^{2} + A C^{2}$ [Since, AC = BC]
$A B^{2} = 2 A C^{2}$

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Similar questions

A B^{2} = 2 A C^{2}

$A B C$ is an isosceles triangle right angled at $C$ . Prove that $A B^{2} = 2 A C^{2}$

A B C

C .

A B^{2} = 2 A C^{2}

A B^{2} = 2 A C^{2}

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