If Abhishek travels at a speed of 25 km/hr in his car, he reaches office 4 minute late. If he drives at a speed of 30 km/hr, he reaches office 10 minutes early. Find the distance between his office and his home.

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Solution

Let x be the required distance.
x/s=t
Now, by 1 st condition,
x/25=t+1/15................(4 minutes=1/15 hours)
And by the second equation,
x/30=t-1/6
On equating both the equations, we get
x/25 -1/15=x/30 +1/6
So, x=35 km

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If Abhishek travels at a speed of 25 km/hr in his car, he reaches office 4 minute late. If he drives at a speed of 30 km/hr, he reaches office 10 minutes early. Find the distance between his office and his home.

Let x be the required distance. x/s=t Now, by 1 st condition, x/25=t+1/15................(4 minutes=1/15 hours) And by the second equation, x/30=t-1/6 On equating both the equations, we get x/25 -1/15=x/30 +1/6 So, x=35 km

Let x be the required distance.
x/s=t
Now, by 1 st condition,
x/25=t+1/15................(4 minutes=1/15 hours)
And by the second equation,
x/30=t-1/6
On equating both the equations, we get
x/25 -1/15=x/30 +1/6
So, x=35 km