If abscissa is one third of the ordinate of a point $P (x, 6)$ then find the value of $x$ .

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Solution

Given the abscissa of the point $P (x, 6)$ is one-third of the ordinate.

The abscissa and the ordinate of the point $P$ are $x$ and $6$ respectively.

Then, we have,

$x = \frac{1}{3} \times 6$

or, $x = 2$ .

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If abscissa is one third of the ordinate of a point P(x,6) then find the value of x.

Given the abscissa of the point P(x,6) is one-third of the ordinate.The abscissa and the ordinate of the point P are x and 6 respectively.Then, we have,x=13×6or, x=2.

If abscissa is one third of the ordinate of a point $P (x, 6)$ then find the value of $x$ .

Given the abscissa of the point $P (x, 6)$ is one-third of the ordinate.

The abscissa and the ordinate of the point $P$ are $x$ and $6$ respectively.

Then, we have,

$x = \frac{1}{3} \times 6$

or, $x = 2$ .