If the ordinate is twice the abscissa, then find the point on the line 7x - 3y = 8.

(8,16)

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(2,4)

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(3,6)

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(6,3)

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Solution

The correct option is A
(8,16)

Let, the abscissa x = k and the ordinate y = 2k.
Putting the value in the given equation:
7(k) - 3(2k) = 8
$\Rightarrow k = 8$
Thus, Abcissa x = k = 8 and ordinate y = 2k = 16.
Thus, the given point is (8,16).

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If the ordinate is twice the abscissa, then find the point on the line 7x - 3y = 8.

The correct option is A (8,16) Let, the abscissa x = k and the ordinate y = 2k. Putting the value in the given equation: 7(k) - 3(2k) = 8 ⇒k=8 Thus, Abcissa x = k = 8 and ordinate y = 2k = 16. Thus, the given point is (8,16).

The correct option is A
(8,16)

Let, the abscissa x = k and the ordinate y = 2k.
Putting the value in the given equation:
7(k) - 3(2k) = 8
$\Rightarrow k = 8$
Thus, Abcissa x = k = 8 and ordinate y = 2k = 16.
Thus, the given point is (8,16).