If the ordinate is twice the abscissa, then find the point where
$7 x - 3 y = 8.$

(8,16)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(2,4)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(3,6)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(6,3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
(8,16)

Let, the abscissa x = k and the ordinate y = 2k.

Substituting the value in the given equation:

$7 x - 3 y = 8.$

$7 (k) - 3 (2 k) = 8$

$\Rightarrow k = 8$

Thus, Abscissa x = k = 8 and ordinate y = 2k = 16.

Thus, the given point is (8,16).

Suggest Corrections

Similar questions

If the ordinate is twice the abscissa, then find the point on the line 7x - 3y = 8.

If the ordinate (value of the ' $y$ ' coordinate) is twice the abscissa (value of the ' $x$ ' coordinate), then find the point where $7 x - 3 y = 8$ .

Find such a point whose ordinate is twice the abscissa and it also passes through the line 7x - 3y = 8.

Find the point on 5x - 3y = 4 where the ordinate is equal to the abscissa

The ordinate of a point is twice its abscissa and the point lies on the line 7x - 3y = 8. What are the coordinates of the point?

Join BYJU'S Learning Program

If the ordinate is twice the abscissa, then find the point where 7x−3y=8.

The correct option is A (8,16) Let, the abscissa x = k and the ordinate y = 2k. Substituting the value in the given equation: 7x−3y=8. 7(k)−3(2k)=8 ⇒k=8 Thus, Abscissa x = k = 8 and ordinate y = 2k = 16. Thus, the given point is (8,16).

If the ordinate is twice the abscissa, then find the point where
$7 x - 3 y = 8.$

The correct option is A
(8,16)

Let, the abscissa x = k and the ordinate y = 2k.

Substituting the value in the given equation:

$7 x - 3 y = 8.$

$7 (k) - 3 (2 k) = 8$

$\Rightarrow k = 8$

Thus, Abscissa x = k = 8 and ordinate y = 2k = 16.

Thus, the given point is (8,16).