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Question

If all the roots of z3+az2+bz+c=0 are of unit modulus, then

A
|34i+b|>8
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B
|c|3
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C
|34i+a|8
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D
|34i+a|>8
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Solution

The correct option is C |34i+a|8
Let α,β,γ are roots of the equation
α=aα β=bα β γ=c
Now, |α+β+γ||α|+|β|+|γ||a|3|αβ+βγ+γα||αβ|+|βγ|+|γα||b|3|αβγ|=|α||β||γ|=1|c|=1
Now, |34i+b||34i+b||34i|+|b|5+3=8
Similarly, |34i+q|8

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