If all the roots of z3+az2+bz+c=0 are of unit modulus, then
A
|3−4i+b|>8
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B
|c|≥3
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C
|3−4i+a|≤8
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D
|3−4i+a|>8
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Solution
The correct option is C|3−4i+a|≤8 Let α,β,γ are roots of the equation ∴∑α=−a∑αβ=bαβγ=−c Now, |α+β+γ|≤|α|+|β|+|γ|⇒|a|≤3|αβ+βγ+γα|≤|αβ|+|βγ|+|γα|⇒|b|≤3|αβγ|=|α||β||γ|=1⇒|c|=1 Now, |3−4i+b|≤|3−4i+b|≤|3−4i|+|b|≤5+3=8 Similarly, |3−4i+q|≤8