If $α = 0.98$ and current through emitter $i_{e} = 20$ mA, the value of $β$ is?

4.9

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49

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96

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9.6

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Solution

The correct option is B $49$
We know that, $α = \frac{I_{C}}{I_{E}} I_{C} = α I_{E}$
$I_{C} = 0.98 \times 20 = 19.6 m A$
We have, $I_{E} = I_{C} + I_{B}$
$I_{B} = 20 - 19.6 = 0.4 m A$
$β = \frac{I_{C}}{I_{B}} = \frac{19.6}{0.4} = 49$

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