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Question

If α=30 and β=60, then the value of sinα+sec2α+tan(α+15)tanβ+cot(β2+15)+tanα is

A
726(433)
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B
3(43)
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C
12(31)
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D
32
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Solution

The correct option is A 726(433)
sinα+sec2α+tan(α+15)tanβ+cot(β2+15)+tanα

=sin30+sec60+tan45tan60+cot45+tan30

=12+2+13+1+13

=732(4+3)=726(433)

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