If α,β are roots of the equation x2−p(x+1)−c=0, then
(α+1)(β+1)=
1-c
Given equation:
x2−p(x+1)−c=0
or
x2−px−p−c=0
Also, α and β are the roots of the equation
Sum of the roots α+β=p.
Product of the roots = αβ=-(c+p)
Then, α+1 β+1= αβ+ α + β+1 =-(c+p)+p+1
=-c-p+p+1=1-c