If - - - are roots of x3 - x2 - 1- 0 the value of 1 - -1 - - - 1 - -1 - - - 1 - -1 - - -

The correct option is A 5 Adding and subtracting 1 from each term, 2( 1/1 α + 1/1 β + 1/1 γ) 3 The numerator becomes 1 on expanding and hence ...

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If $α, β, γ$ are roots of $x^{3} - x^{2} - 1 = 0$ the value of $\frac{1 + α}{1 - α} + \frac{1 + β}{1 - β} + \frac{1 + γ}{1 - γ} =$ .

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If $α, β, γ$ are the roots of $x^{3} - x^{2} - 1 = 0,$ then the value of $\frac{1 + α}{1 - α} + \frac{1 + β}{1 - β} + \frac{1 + γ}{1 - γ} =$

α, β, γ

x^{3} + 4 x + 1 = 0

(α + β)^{- 1} + (β + γ)^{- 1} + (γ + α)^{- 1}

$I f α, β, γ a r e r o o t s e q u a t i o n x^{3} + a x^{2} + b x + c = 0, t h e n α^{- 1} + β^{- 1} + γ^{- 1} =$

α, β, γ

x^{3} + a x + b = 0

(α + β)^{- 1} + (β + γ)^{- 1} + (γ + α)^{- 1} =

If α, β, γ are the roots of the equation $x^{3} + 4 x + 1 = 0$ ,then $(α + β)^{- 1} + (β + γ)^{- 1} + (γ + α)^{- 1} =$

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