If $α$ is the degree of dissociation of $N a_{2} S O_{4}$ , the vant Hoff's factor (i) used for calculating the molecular mass is

1 + α

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α

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1 + 2 α

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1 - 2 α

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Solution

The correct option is C $1 + 2 α$
$N a_{2} S O_{4}      1 - α ⇌ 2 N a^{+}      2 α + S O_{4}^{2 -}      α$
Total no. of ions after dissociation = $1 + 2 α$
vant Hoff's factor, $i = \frac{N o . o f p a r t i c l e s a f t e r d i s s o c i a t i o n}{N o . o f p a r t i c l e s b e f o r e d i s s o c i a t i o n} = 1 + 2 α$

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