If an albino man marries a normal woman and 50 offsprings are albino and 50 are normal, the woman is
A
Heterozygous normal
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B
Homozygous normal
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C
Heterozygous carrier
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D
None of the above
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Solution
The correct option is C Heterozygous carrier When 50% are normal and 50% are albinic, the mother will be a carrier. Human females have two X chromosomes and thus homozygous dominant, homozygous recessive and heterozygous conditions are possible. Albinism is an autosomal recessive trait. The genotype of such mother would be 'Aa', i.e., one recessive gene 'a' responsible for the absence of melanin and one dominant gene responsible for the presence of melanin would be present. So the mother would be heterozygotic carrier.