Question

If an angel visits an asteroid called $B612$ which has a radius of $20m$ and mass of $104kg$, what will be the acceleration due to gravity in $B612$?

Answer 1

$M=104Kg$

$R=20m$

$\therefore g=\frac{GM}{R^2}=\frac{6.67\times {10}^{-11}\times 104}{20\times 20}$

$=1.7342\times {10}^{-11}m{s}^{-2}$