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Question

# If an element A shows two oxidation states +2 and +3. A forms oxides in such a way that they have a ratio 1 : 3 in a compound, the formula of the compound will be

A
A8O11
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B
A4O11
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C
A9O11
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D
A5O11
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Solution

## The correct option is A A8O11As we can see from the options, the number of oxygen atoms in the oxide of element A is 11. Let us consider that the number of atoms of element A in +2 oxidation state to be x and the number of atoms of element A in +3 oxidation state to be 3x For a neutral molecule, the number of +ve and −ve charges should be equal and their sum will be zero. ∴(+2×x)+(+3×3x)+(−2×11)=0 On solving we get, 11x−22=0, x=2 So, the number of atoms of element A in +2 oxidation state, x=2 And the number of atoms of element A in +3 oxidation state, 3x=3×2=6 ∴ The total number of atoms of element A in the compound =2+6=8 The Molecular formula of the compound is A8O11

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