Question

If an object is placed at the centre of curvature of a concave mirror, the image formed will be

• A. of same size.
• B. inverted.
• C. real.
• D. magnified.

Answer 1

Answer: (A), (B), (C)

The correct options are
A of same size.
B inverted.
C real.

$\frac{1}{v}=\frac{1}{f}-\frac{1}{u};f=-\frac{R}{2}\&u=-R\left(forconcavemirror\right)$

$\frac{1}{v}=\frac{1}{-\frac{R}{2}}-\frac{1}{-R}$

$v=-R$

m= -v/u =1

therefore from above obtained values, we can say

If an object is placed at centre of curvature of a concave mirror, light rays meet to form an image which is real, inverted and at the same size as that of the object. The image formed is not magnified.