If an object is submerged in water, then taken out and submerged in mercury. Then which of the following will be true?

The volume of the object submerged in water = volume of the object submerged in mercury.

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The volume of the object submerged in water > volume of the object submerged in mercury.

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Upthrust in water > upthrust in mercury.

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Upthrust in mercury > upthrust in water.

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Solution

The correct options are
B
The volume of the object submerged in water > volume of the object submerged in mercury.

D
Upthrust in mercury > upthrust in water.

Since the density of mercury > density of water.

Upthrust in mercury will be greater than upthrust in water and so the volume of the object submerged in mercury will be lesser than in water.

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