The correct option is C 118
Let A be the event that coin shows head.
Let B be the event that sum of the numbers is 9.
ThenB=((3, 6), (4, 5), (5, 4), (6, 3)}
Probability of getting head, P(A)=12
There are six possiblities for each dice.
Therefore, number of elements in the sample space for dice throw=6×6=36
Therefore, P(B)=436
Thus, probability of getting head and sum of the numbers as 9
=12×436=472=118