Question

If angular displacement of a particle is given by $\theta =a-bt+c{t}^2$, then find its angular velocity.

• A. $-b+2ct$
• B. $-b+ct$
• C. $b+2ct$
• D. $-b-2ct$

Answer 1

The correct option is A $-b+2ct$

Angular velocity is given by $\omega =\frac{d\theta }{dt}$ Here $\theta =a-bt+c{t}^2$
Hence, $\omega =\frac{d\theta }{dt}=\frac{d(a-bt+c{t}^2)}{dt}=-b+2ct$