If Anil goes the school from his home by an average speed of $5 k m / h$ , he reaches there at the correct time. If however his average speed is $4 k m / h$ , he reaches there $15 m i n$ late. Find the distance of the school from his home ?

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Solution

Let distance between school and home= $x k m$ .

Time taken to reach school at $4 \frac{k m}{h r} = \frac{x}{4} h r s$ .

Time taken to reach school at $5 \frac{k m}{h r} = \frac{x}{5} h r s$ .

$\frac{x}{4} - \frac{15}{60} = \frac{x}{5}$

$\frac{x}{4} - \frac{x}{5} = \frac{15}{60}$

$\frac{5 x - 4 x}{20} = \frac{1}{4}$

$5 x - 4 x = \frac{20}{4}$

$x = 5$

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If Anil goes the school from his home by an average speed of 5 km/h, he reaches there at the correct time. If however his average speed is 4 km/h, he reaches there 15 min late. Find the distance of the school from his home ?

Let distance between school and home=xkm.Time taken to reach school at 4kmhr=x4hrs.Time taken to reach school at 5kmhr=x5hrs.x4−1560=x5x4−x5=15605x−4x20=145x−4x=204x=5

If Anil goes the school from his home by an average speed of $5 k m / h$ , he reaches there at the correct time. If however his average speed is $4 k m / h$ , he reaches there $15 m i n$ late. Find the distance of the school from his home ?