If Anish is moving along the boundary of a triangular field of sides 35m, 53m and 66m and you are moving along the boundary of a circular field whose area is double the area of the triangular field, then the radius of the circular field is :
(Take pi=227)
14√3 m
Area of Δ=√77(42)(24)(11)=924
πr2=2(924)
r2=2×924×722
r2=588
r=14√3 m