Question

If α, β are the zeros of f (x) = 2x² + 6x − 6, then

(a) α + β = αβ
(b) α + β > αβ
(c) α + β < αβ
(d) α + β + αβ = 0

Answer 1

$$\begin{gathered} \left(\text{a}\right)\mathrm{\alpha }+\mathrm{\beta }=\mathrm{\alpha \beta } \\ \text{Given:}\mathrm{\alpha }\text{and}\mathrm{\beta }\text{are zeroes of 2}{x}^2+6x-6. \\ \text{Then}\mathrm{\alpha }\text{+}\mathrm{\beta }\text{=}\frac{-6}{2}=-3\text{and}\mathrm{\alpha \beta }\text{=}\frac{-6}{2}=-3 \\ \therefore \mathrm{\alpha }+\mathrm{\beta }=\mathrm{\alpha \beta } \end{gathered}$$